Page 5 - Digi Notes - MATHS - 18.03.2016
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A quadratic equation + + = have two roots given by
− − √ −
=
− − √ −
=
Comparing the values obtained by given Quadratics to get the correct relation:
Note: If any one of the sign among the two/four signs get reversed; then the
answer is always – “The relation cannot be determined”
Now let us solve some examples:
Find the relation between x and y
2
2
I. 3x –19x + 28 = 0 II. 5y – 18y+16 = 0
2
I. 3x – 12x – 7x + 28 = 0
3x (x – 4) – 7(x–4)=0
(x – 4) (3x – 7) = 0
x=4,
2
II. 5y –10y –8y+16=0
5y(y–2)–8(y–2)=0
(y – 2) (5y – 8) = 0
y=2,
Page 5 of 12
www.mahendraguru.com
A quadratic equation + + = have two roots given by
− − √ −
=
− − √ −
=
Comparing the values obtained by given Quadratics to get the correct relation:
Note: If any one of the sign among the two/four signs get reversed; then the
answer is always – “The relation cannot be determined”
Now let us solve some examples:
Find the relation between x and y
2
2
I. 3x –19x + 28 = 0 II. 5y – 18y+16 = 0
2
I. 3x – 12x – 7x + 28 = 0
3x (x – 4) – 7(x–4)=0
(x – 4) (3x – 7) = 0
x=4,
2
II. 5y –10y –8y+16=0
5y(y–2)–8(y–2)=0
(y – 2) (5y – 8) = 0
y=2,
Page 5 of 12
www.mahendraguru.com
