Page 4 - Digi-Notes-23-03-2016-Reasoning-Updated_Neat
P. 4
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St- A ≥ B ≥ C (A > B > C) A > C
(A > B = C) A > C A > C
(A = B > C) A > C
(A > B = C) A > C A = C
In last case there is two different possibility
1. A > C
2. A = C
So conclusion should hold both possibility i.e. - A ≥ C
If not then there will be either or in order to complete conclusion
So Either A > C or A = C
How to conclude-
Step 1- Check whether all inequality symbols between those two
elements (which we are concluding) are in same order or not.
If yes! Then
Step 2- Check between them is there any single inequality symbols
(>, <) between them or not
If yes! Then that single inequality symbol should be there in
conclusion to make it right.
If No! then double inequality symbol (≥ ≤) should be there between
conclusion. See example below-
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St- A ≥ B ≥ C (A > B > C) A > C
(A > B = C) A > C A > C
(A = B > C) A > C
(A > B = C) A > C A = C
In last case there is two different possibility
1. A > C
2. A = C
So conclusion should hold both possibility i.e. - A ≥ C
If not then there will be either or in order to complete conclusion
So Either A > C or A = C
How to conclude-
Step 1- Check whether all inequality symbols between those two
elements (which we are concluding) are in same order or not.
If yes! Then
Step 2- Check between them is there any single inequality symbols
(>, <) between them or not
If yes! Then that single inequality symbol should be there in
conclusion to make it right.
If No! then double inequality symbol (≥ ≤) should be there between
conclusion. See example below-
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