Page 5 - Digi-Notes-23-03-2016-Reasoning-Updated_Neat

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St- A > B > C A > C

St- A ≥ B > C A > C In all these statements there are one

St- A > B ≥ C A > C single inequality symbol so

Conclusion are having singe

Inequality symbol

St- A ≥ B ≥ C A ≥ C In this statement there is no single

Symbol so conclusion is having

Double inequality symbol.

If Symbols between two elements are in reverse order then-

St- A > B < C or A < B > C or A ≥ B ≤ C or A ≤ B ≥ C or A ≠ B ≠ C

Or A ≠ B > C or A ≠ B < C or A ≠ B ≥ C or A ≠ B ≤ C

Then there will be three possibility- > < =

So in order make conclusion right there should be all these three

Symbol should be together which is not possible so in such

Cases only either or will come in to play.

i.e. A ≤ C or A > C

A ≥ C or A < C

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