Page 18 - Surviving Chemistry BFF Homework Helper and Test Prep Preview
P. 18
What pressure in atm is equivalent to 259 kPa?
1.0 atm
1 atm = 101.3 kPa 259 kPa x ----------- = 2.6 atm
101.3 kPa
numerical setup calculated result
What volume of He(g) in milliliters is equivalent
to 1.33 L of He(g)?
1.33 L 1 L
1 L = 1000 mL --------- = ----------- numerical setup
X 1000 mL
calculated
X = (1000 mL)(1.33) = 1330 mL result.
Only Kelvin temperature should be used in gas
law calculations.
o
o (See example conversions from C to K on pg. 12)
K = 273 + C
A 50. mL sample of a gas is at 2.0 atm and 320 K.
What will be the new volume of the gas at STP?
P1V1 P2V2 (50.)(2.0) (1.0 ) (V2) Standard
------ = ------- --------- = ----------
Temperature
T1 T2 320 273 Pressure
85 ml = V2
At constant temperature, what is the new volume
of a 3.0 L sample of O2 gas if its pressure is changed
from 0.50 atm to 0.25 atm?
(0.50)(3.0) = (0.25)(V2) numerical setup
P1V1 = P2V2
6.0 L = V2 calculated result
The volume of a gas is 25 mL at 280 K. If the
pressure is held constant, at what temperature would
the volume of the gas increase to 75 mL?
V1 V2 25 75
---- = ----- ----- = ----- numerical setup
T1 T2 280 T2
840 K = T2 calculated result
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