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Constructed Response . Topic 6: Moles and Stoichiometry
Set G: Type of reaction, conservation of mass, mole to mole problems in equations
Base your answers to questions 18 through 20 on the balanced chemical equation below.
2 H2O ------------ > 2 H2 + O2
Show work and write your answers here.
18. What is the total number of moles of O2 produced 18.
when 8 moles of H2O is completely consumed?
19. How does the balanced chemical equation show 19.
Teacher Preview Copy
the Law of Conservation of Mass?
20. What type of reaction does this equation represents. 20.
Set H: Balanced equation, mole –mole problems in equations
Base your answers to questions 21 and 22 on the balanced equation below.
4 Al(s) + 3O2(g) ------- > 2Al2O3(s)
Show work and answer here
Teacher Preview Copy
21. What is the total number of moles of O2(g) that 21.
must react completely with 8.0 moles of Al(s) in
order to form Al2O3(s)
22. What type of reaction is represented by the above 22.
equation
Copyright©2010 E3 Scholastic Publishing. All Rights Reserved. SurvivingChem.com 383
Set G: Type of reaction, conservation of mass, mole to mole problems in equations
Base your answers to questions 18 through 20 on the balanced chemical equation below.
2 H2O ------------ > 2 H2 + O2
Show work and write your answers here.
18. What is the total number of moles of O2 produced 18.
when 8 moles of H2O is completely consumed?
19. How does the balanced chemical equation show 19.
Teacher Preview Copy
the Law of Conservation of Mass?
20. What type of reaction does this equation represents. 20.
Set H: Balanced equation, mole –mole problems in equations
Base your answers to questions 21 and 22 on the balanced equation below.
4 Al(s) + 3O2(g) ------- > 2Al2O3(s)
Show work and answer here
Teacher Preview Copy
21. What is the total number of moles of O2(g) that 21.
must react completely with 8.0 moles of Al(s) in
order to form Al2O3(s)
22. What type of reaction is represented by the above 22.
equation
Copyright©2010 E3 Scholastic Publishing. All Rights Reserved. SurvivingChem.com 383