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Topic 8: Acids, Bases, and Salts

17. Alternate theory of acids and bases: Recalling concept facts and definitions
1. According to an alternate theory, an acid is any species that can
1) Donate a proton 3) Accept a proton

2) Donate an electron 4) Accept an electron

2. According to an alternate theory, a base in an acid-base reaction is any species that can
1) Donate a proton 3) Accept a proton
2) Donate an electron 4) Accept an electron

3. According to an “alternate theory” of acids and bases, H2O will act as a base in a reaction if
1) Donates OH to another species in the reaction
-
+
2) Donates H ion to another species in the reaction
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3) Accepts OH ion from another species in the reaction
+
4) Accepts H ion from another species in the reaction

4. According to an “alternate theory” of acids and bases, H2O will act as an acid in a reaction if
-
1) Donates OH to another species in the reaction
+
2) Donates H ion to another species in the reaction
-
3) Accepts OH ion from another species in the reaction
4) Accepts H ion from another species in the reaction
+

18. Reaction of acids with metals: Determining which metal will react

1. According to Reference Table J, which metal will react with hydrochloric acid to produce hydrogen
gas?
1) Ag 2) Hg 3) Cu 4) Ni

2. Under standard conditions, which metal will react spontaneously with 1 M HNO3?
4) Au
1) Mg

2) Ag
3) Hg

3. Which of these metals will not produce a reaction with sulfuric acid?
1) Ca 2) Au 3) Zn 4) Li

4. According to Reference Table J, which reaction will not occur under STP?
1) Sn(s) + 2HCl (aq) --------------- H2 (g) + SnCl2 (aq)
2) Cu (s) + 2 HCl (aq) --------------- H2 (g) + CuCl2 (aq)
3) Ba(s) + 2 HCl (aq) ---------------- H2(g) + BaCl2 (aq)
4) Pb (s) + 2 HCl (aq) ---------------- H2(g) + PbCl2 (aq)

5. Which equation is showing a reaction that is likely to occur under standard conditions?
1) Au(s) + 2HBr(aq) --------------- H2 (g) + AuBr2 (aq)
2) Cu (s) + 2HBr (aq) --------------- H2 (g) + CuBr2 (aq)
3) Hg(s) + 2HBr(aq) ---------------- H2 (g) + HgBr2 (aq)
4) Cr (s) + 2HBr(aq) ---------------- H2 (g) + CrBr2 (aq)

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